挺方便的,自己写个脚本,就不用登陆邮箱发送附件了.
summary:
1.SMTP和HTTP类似.都是头里面有一些相关信息,content-type
,encoding啊,etc.Message是基类.用字典映射的方式可以读取和设置head中选项的值.MIMEText等MIME类型继承自MIMEBase,MIMEBase继承自Message.
他们都没有自己定义方法,都是用Message的
MIMEMultipart可以通过attach添加多个MIME的文件.所以用它添加附件
2.不同附件文件类型不同,head里面有个Content-Disposition的选项,可以设置文件类型.要上传不同文件类型,就要让python通过mimestypes.guess_type()识别文件类型
3.读取二进制文件的时候,打开方式要为"rb",因为可能会有和EOF编码相同的字节.这样python认为找到了文件的结尾,停止读入.
3.lambda: 随时定义一个函数,避免许多单行的函数定义
# -*- coding: cp936 -*-
import smtplib, mimetypes
from email.mime.text import MIMEText
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
msg=MIMEMultipart()
msg["From"] = "xxx@xxx.com"
msg["To"] = "xxx@xxx.com"
msg["Subject"] = "Test SMTP by Python"
text=MIMEText("This is text content.")
msg.attach(text)
filename=r'F:\Novel\peach.zip'
ctype,encoding = mimetypes.guess_type(filename)
if ctype is None or encoding is not None:
ctype='application/octet-stream'
maintype,subtype = ctype.split('/',1)
#att=MIMEImage(open(filename,'r').read(),subtype)
att=MIMEImage(open(filename, 'rb').read(),subtype)
print ctype,encoding
att["Content-Disposition"] =
'attachmemt;filename="peach.zip"'
msg.attach(att)
smtp=smtplib.SMTP()
smtp.connect("smtp.163.com")
smtp.login("xxx@xxx.com","password")
smtp.sendmail(msg["From"],msg["To"],msg.as_string())
smtp.quit()
print 'send mail successfully'
